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# Uttara Bank Ltd. Exam Questions Solution 2022

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## Uttara Bank Ltd. Exam Questions Solution

NOTE :

Post: Probationary Officer

Written Exam Date:  2022

Written Exam Time: 3.00 PM to 4.30 PM

##### Full Question Solution Given Below : Question-1

From several apples, a man sells half the number of existing apples plus 1 to the first customer, sells 1/3 of the remaining apple plus 1 to the second consumer, and sells 1/5 of the remaining apple plus 1 to the third consumer. He then finds that he has 3 apples left. How many apples did he have originally?

Solution:
Suppose,
The number of apples =x
He sells apples to the first customer
=(x/2+1)=(x+2)/2
Remaining Apples
=x-(x+2)/2
=(x-2)/2
He sells apples to the second customer
=1/3{(x-2)/2}+1
=(x+4)/6
Remaining apples
={(x-2)/2}-{(x+4)/6}
=(2x-10)/6
=(x-5)/3
He sells the third customer
=1/5{(x-5)/3}+1
=(x+10)/15
Remaining apples
={(x-5)/3}-{(x+10)/15}
=(4x-35)/15
According to the question,
(4x-35)/15=3
Or, x=20

Question-2 Question-3

A farmer sold a cow & Ox for Tk 80,000 and got a profit on 20% on the cow & 25%on the ox. If he sells the cow and the ox for tk.82,000 and got a profit of 25% on the cow and 20% on the ox. Find the individual cost price of both?[Uttara Bank _PO_2018]
Solution:
Let
The cost price of a cow be x tk
The cost price of Ox be y tk
According to the first condition,
120%x + 125% Y=80,000
Or, 120x +125y=80,000*100
Or, 24x+25y=16,00,000……….(i)
Again, Second condition
125%x + 120%y= 82,000
Or, 125x + 120y=82,000*100
Or, 25x +24y=16,40,000———-(ii)
(i)*25-(ii)*24=»
600x + 625y=4,00,00,000
600x + 576y=3,93,60,000
—————————————–
Or, 49y=640000
Or, y=13061.22
Putting the value of y=13061.22 equation (i)=»
24x=1600000-25*13061.22
Or, 24x =1600000-326530.61
Or, 24x=1273469.4
Or,x=53061.22 